MODEL PREDICTION · 2026-09-28
● HARD

B. Van De Zandschulp vs V. Royer — prediction

Beijing
✓ Correct
ZANDSCHULPWIN PROBABILITYROYER
66%
model prob.
@1.60
odds · 63% impl.
⏱Rest 3d vs 2d◐Hard 49%🎾Serve 63%📈Form 7/10
CONDITIONS OF THE MATCH◆ in the model◇ context
Surface◆
Hard

Consistent bounce, medium-fast: neutral conditions, no style favored.

Temperature◇
23°C

Mild: neutral conditions.

Humidity◇
64%

Humid air: the ball loses some speed.

Wind◇
6 km/h

Light wind: no noticeable effect.

Surface feeds the model (surface specialization is one of its factors). Weather and altitude are context we publish for you — they do NOT move the probability.

OUR MODEL'S REASONING

›Ranking: #40 vs #104 (better ranked)

›Recent form: 7/10 in recent matches

Calibrated model probability (~65% out-of-sample accuracy). Not a guarantee: the model ≈ the market on average, so the odds already capture almost all the edge. 18+ · gamble responsibly.
@1.51
fair odds
+5.9%
expected value
BREAKDOWN · MODEL ANALYSIS

The model makes B. Van De Zandschulp the favorite with a 66% win probability, against V. Royer's 34% — a solid favorite, though Royer keeps real chances. Converted to odds, that probability is worth about @1.51; the offered odds are around @1.60 (a 63% implied), slightly above the market, so the model is a touch more optimistic.

Several factors explain the number: #40 vs #104 (better ranked); 7/10 in recent matches.

Read it with perspective. Our probability is calibrated — when the model says 66%, that outcome happens roughly that percentage of the time, with ~65% out-of-sample accuracy — but being the favorite is not being the winner: roughly 34 out of every 100 times Royer wins. The model also tends to agree with the market, so the odds already capture almost all the edge: don't take it as a sure value. This is informational analysis, not a betting recommendation. 18+ · play responsibly.

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