R. Sramkova vs A. Blinkova — prediction

The model makes R. Sramkova the favorite with a 51% win probability, against A. Blinkova's 49% — a tight match, without a wide margin. Converted to odds, that probability is worth about @1.97; the offered odds are around @2.10 (a 48% implied), slightly above the market, so the model is a touch more optimistic.

Several factors explain the number: #141 vs #105; 2/10 in recent matches.

Read it with perspective. Our probability is calibrated — when the model says 51%, that outcome happens roughly that percentage of the time, with ~64% out-of-sample accuracy — but being the favorite is not being the winner: roughly 49 out of every 100 times Blinkova wins. The model also tends to agree with the market, so the odds already capture almost all the edge: don't take it as a sure value. Watch out for: Coming off 5 losses in a row. This is informational analysis, not a betting recommendation. 18+ · play responsibly.