J. Brooksby vs A. Walton — prediction
Consistent bounce, medium-fast: neutral conditions, no style favored.
Mild: neutral conditions.
Very humid air: the ball gets heavy and points stretch out.
Light wind: no noticeable effect.
Surface feeds the model (surface specialization is one of its factors). Weather and altitude are context we publish for you — they do NOT move the probability.
›Ranking: #81 vs #85 (better ranked)
›Recent form: 4/10 in recent matches
›Model 51% vs market 57% → the model sees it as less likely than the odds
!Returning from a long layoff (30d) — possible rustiness
The model makes J. Brooksby the favorite with a 51% win probability, against A. Walton's 49% — a tight match, without a wide margin. Converted to odds, that probability is worth about @1.97; the offered odds are around @1.75 (a 57% implied), slightly below the market, so the model is a touch more cautious.
Several factors explain the number: #81 vs #85 (better ranked); 4/10 in recent matches; model 51% vs market 57% → the model sees it as less likely than the odds.
Read it with perspective. Our probability is calibrated — when the model says 51%, that outcome happens roughly that percentage of the time, with ~65% out-of-sample accuracy — but being the favorite is not being the winner: roughly 49 out of every 100 times Walton wins. The model also tends to agree with the market, so the odds already capture almost all the edge: don't take it as a sure value. Watch out for: Returning from a long layoff (30d) — possible rustiness. This is informational analysis, not a betting recommendation. 18+ · play responsibly.